Integrand size = 13, antiderivative size = 98 \[ \int x \left (a+b x^4\right )^{3/4} \, dx=\frac {3 a x^2}{5 \sqrt [4]{a+b x^4}}+\frac {1}{5} x^2 \left (a+b x^4\right )^{3/4}-\frac {3 a^{3/2} \sqrt [4]{1+\frac {b x^4}{a}} E\left (\left .\frac {1}{2} \arctan \left (\frac {\sqrt {b} x^2}{\sqrt {a}}\right )\right |2\right )}{5 \sqrt {b} \sqrt [4]{a+b x^4}} \]
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Time = 0.04 (sec) , antiderivative size = 98, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.385, Rules used = {281, 201, 235, 233, 202} \[ \int x \left (a+b x^4\right )^{3/4} \, dx=-\frac {3 a^{3/2} \sqrt [4]{\frac {b x^4}{a}+1} E\left (\left .\frac {1}{2} \arctan \left (\frac {\sqrt {b} x^2}{\sqrt {a}}\right )\right |2\right )}{5 \sqrt {b} \sqrt [4]{a+b x^4}}+\frac {1}{5} x^2 \left (a+b x^4\right )^{3/4}+\frac {3 a x^2}{5 \sqrt [4]{a+b x^4}} \]
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Rule 201
Rule 202
Rule 233
Rule 235
Rule 281
Rubi steps \begin{align*} \text {integral}& = \frac {1}{2} \text {Subst}\left (\int \left (a+b x^2\right )^{3/4} \, dx,x,x^2\right ) \\ & = \frac {1}{5} x^2 \left (a+b x^4\right )^{3/4}+\frac {1}{10} (3 a) \text {Subst}\left (\int \frac {1}{\sqrt [4]{a+b x^2}} \, dx,x,x^2\right ) \\ & = \frac {1}{5} x^2 \left (a+b x^4\right )^{3/4}+\frac {\left (3 a \sqrt [4]{1+\frac {b x^4}{a}}\right ) \text {Subst}\left (\int \frac {1}{\sqrt [4]{1+\frac {b x^2}{a}}} \, dx,x,x^2\right )}{10 \sqrt [4]{a+b x^4}} \\ & = \frac {3 a x^2}{5 \sqrt [4]{a+b x^4}}+\frac {1}{5} x^2 \left (a+b x^4\right )^{3/4}-\frac {\left (3 a \sqrt [4]{1+\frac {b x^4}{a}}\right ) \text {Subst}\left (\int \frac {1}{\left (1+\frac {b x^2}{a}\right )^{5/4}} \, dx,x,x^2\right )}{10 \sqrt [4]{a+b x^4}} \\ & = \frac {3 a x^2}{5 \sqrt [4]{a+b x^4}}+\frac {1}{5} x^2 \left (a+b x^4\right )^{3/4}-\frac {3 a^{3/2} \sqrt [4]{1+\frac {b x^4}{a}} E\left (\left .\frac {1}{2} \tan ^{-1}\left (\frac {\sqrt {b} x^2}{\sqrt {a}}\right )\right |2\right )}{5 \sqrt {b} \sqrt [4]{a+b x^4}} \\ \end{align*}
Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.
Time = 7.75 (sec) , antiderivative size = 51, normalized size of antiderivative = 0.52 \[ \int x \left (a+b x^4\right )^{3/4} \, dx=\frac {x^2 \left (a+b x^4\right )^{3/4} \operatorname {Hypergeometric2F1}\left (-\frac {3}{4},\frac {1}{2},\frac {3}{2},-\frac {b x^4}{a}\right )}{2 \left (1+\frac {b x^4}{a}\right )^{3/4}} \]
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\[\int x \left (b \,x^{4}+a \right )^{\frac {3}{4}}d x\]
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\[ \int x \left (a+b x^4\right )^{3/4} \, dx=\int { {\left (b x^{4} + a\right )}^{\frac {3}{4}} x \,d x } \]
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Result contains complex when optimal does not.
Time = 0.56 (sec) , antiderivative size = 29, normalized size of antiderivative = 0.30 \[ \int x \left (a+b x^4\right )^{3/4} \, dx=\frac {a^{\frac {3}{4}} x^{2} {{}_{2}F_{1}\left (\begin {matrix} - \frac {3}{4}, \frac {1}{2} \\ \frac {3}{2} \end {matrix}\middle | {\frac {b x^{4} e^{i \pi }}{a}} \right )}}{2} \]
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\[ \int x \left (a+b x^4\right )^{3/4} \, dx=\int { {\left (b x^{4} + a\right )}^{\frac {3}{4}} x \,d x } \]
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\[ \int x \left (a+b x^4\right )^{3/4} \, dx=\int { {\left (b x^{4} + a\right )}^{\frac {3}{4}} x \,d x } \]
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Timed out. \[ \int x \left (a+b x^4\right )^{3/4} \, dx=\int x\,{\left (b\,x^4+a\right )}^{3/4} \,d x \]
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